Question

3的x次方=4,3的y次方=6,求9的2x-y次方+27x-y次方的值.

Answer 1

9^2x-y+27^x-y

=3^4x-2y+3^3x-3y

=3^4x/3^2y+3^3x/3^3y

=(3^x)^4/(3^y)^2+(3^x)^3/(3^y)^3

=4^4/6^2+4^3/6^3

=256/36+64/216

=64/9+8/27

=192/27+8/27

=200/27