x1=A1cos(wt+φ10) y1=A2cos(wt+φ20) 消去t: x^2/A1^2+y^2/A2^2-2xy*cos(φ20-φ10)/A1A2=[sin(φ20-φ10)]^2 △φ=φ20-φ10=π/2 x^2/A1^2+y^2/A2^2=1
采纳哦
两个互相垂直同频率简谐振动合成的椭圆方程是怎么样的?
x1=A1cos(wt+φ10) y1=A2cos(wt+φ20) 消去t: x^2/A1^2+y^2/A2^2-2xy*cos(φ20-φ10)/A1A2=[sin(φ20-φ10)]^2 △φ=φ20-φ10=π/2 x^2/A1^2+y^2/A2^2=1
采纳哦