Question

如图正比例函数y1=k1x和一次函数,y2=k2x+b的图像相交于点a（4,3）,b为直线y2与y交点且oa=2ob

Answer 1

y1=3/4*x

3 = k2*4+b

oa = 5

ob = 5/2

b=5/2

3=k2*4+5/2 ==> K2 = 1/8

y2=1/8 * x + 5/2