Question

(2又10/27)^-2/3-9/16(根5-1)^0+1/2-根3+根(1-根3)^2

Answer 1

(2又10/27)^-2/3-9/16

=(27/64)^(2/3)-9/16

=9/16-9/16

=0

(根5-1)^0+1/2-根3+根(1-根3)^2

=1+1/2-√3+√3-1

=1/2