Question

数学题导函数一道,急,

Answer 1

解∫(-4,2)e^/x/2/dx

=∫(-4,0)e^/x/2/dx+∫(0,2)e^/x/2/dx

=∫(-4,0)e^(-x/2)dx+∫(0,2)e^(x/2)dx

=(-2e^(-x/2))/(-4,0)+(2e^(x/2))/(0,2)

=(-2e^(-0/2))-[-2e^(-(-4)/2)]+(2e^(2/2))-(2e^(0/2))

=-2+2e^2+2e^1-2×1

=2e^2+2e^1-4