Question

xe^(x^2 -y)求导

Answer 1

y'=xe^(x^2 -y)*(2x-y')+e^(x^2 -y)=xe^(x^2 -y)*(2x)-xe^(x^2 -y)*y'+e^(x^2 -y)

y'+xe^(x^2 -y)*y'=2*x^2*e^(x^2 -y)+e^(x^2 -y)

y'=(2*x^2*e^(x^2 -y)+e^(x^2 -y))/(1+xe^(x^2 -y))