Question

y=1+2sin（x+1）分之（x-1)反函数多少

Answer 1

x=1+2sin[(y-1)/(y+1)]

1-2/(y+1)=arcsin[(x-1)/2]

2/(y+1)=1-arcsin[(x-1)/2]

y=2/{1-arcsin[(x-1)/2]}-1