Question

对数与对数运算㏒a x-y/x+y=-㏒a x+y/x-y 相等吗?1//n ㏒aX=㏒a n√X 相等吗?n√㏒aX=

Answer 1

㏒a x-y/x+y

=㏒a (x+y/x-y)^(-1)

=-㏒a x+y/x-y

1/n ㏒aX

=㏒a X^(1/n)

=㏒a n√X

n√㏒aX=1/n ㏒aX

不对

是㏒a n√X =1/n ㏒aX