(x+y)(x-y)+(x-y)²-(6x²y-2xy²)÷2y
=(x+y)(x-y)+(x-y)²-2xy(3x-y)÷2y
=(x+y)(x-y)+(x-y)²-x(3x-y)
=x^2-y^2+x^2-2xy+y^2-3x^2+xy
=-x^2-xy
=-x(x+y)
=-(-2)(-2+1/3)
= -10/3
化简求值：(x+y)(x-y)+(x-y)²-(6x²y-2xy²)÷2y,其中x=-2,
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