Question

线性代数,把这个行列式化成三角行列式…求解.

Answer 1

=

1 -1 2 -3 1

0 0 -1 0 -2

0 2 0 4 -1

0 -2 1 -5 3

0 0 2 2 -2

= r4+r2+r3,r5+2r2

1 -1 2 -3 1

0 0 -1 0 -2

0 2 0 4 -1

0 0 0 -1 0

0 0 0 2 -6

= (-1)*

1 -1 2 -3 1

0 2 0 4 -1

0 0 -1 0 -2

0 0 0 -1 0

0 0 0 0 -6

= 12.