Question

函数y=|2sin(2x+π/6）|-1的最小值点是?最大值点是?

Answer 1

y=|2sin(2x+π/6）|-1取到最小值时

sin(2x+π/6)=0,

2x+π/6=kπ,

x=kπ/2-π/12,k为整数,

所以最小值点x=kπ/2-π/12,k为整数,

y=|2sin(2x+π/6）|-1取到最大值时

sin(2x+π/6)=±1,

2x+π/6=kπ+π/2,

x=kπ/2+π/6,k为整数,

所以最大值点x=kπ/2+π/6,k为整数,