Question

初一数学题怎么做(x+y的2n-1次方) 乘以 (-x-y的6次方)+(x+y的n+3次方) 乘以 (x+y的n+2次方

Answer 1

(x+y的2n-1次方) 乘以 (-x-y的6次方)+(x+y的n+3次方) 乘以 (x+y的n+2次方)

=(x+y)^(2n-1) ×(x+y)^6+(x+y)^(n+3) ×(x+y)^(n+2)

=(x+y)^(2n-1+6)+(x+y)^(n+2+n+3)

=(x+y)^(2n+5)+(x+y)^(2n+5)

=2(x+y)^(2n+5)

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