Question

导数求根号下x2+1

Answer 1

y'=1/(x+根号下x^2+1)*(x+根号下x^2+1)'

=1/(x+根号下x^2+1)*(1+x/根号下x^2+1)

=1/(x+根号下x^2+1)*(根号下x^2+1+x)/根号下x^2+1

=1/根号下(x^2+1)