已知x=(根号5+1)/2
2x-1=根号5
平方得 4x²-4x+1=5
即x²=x+1
所以x三次方/(x三次方+x+1)
=x(x+1)/[x(x+1)+x+1]
=x/(x+1)
=1/(1+1/x)
=1/[1+2/(√5+1)]
=(√5+1)/(3+√5)
=(1+√5)(3-√5)/(9-5)
=(2√5-2)/4
=(√5-1)/2
已知x=(根号5+1)/2
2x-1=根号5
平方得 4x²-4x+1=5
即x²=x+1
所以x三次方/(x三次方+x+1)
=x(x+1)/[x(x+1)+x+1]
=x/(x+1)
=1/(1+1/x)
=1/[1+2/(√5+1)]
=(√5+1)/(3+√5)
=(1+√5)(3-√5)/(9-5)
=(2√5-2)/4
=(√5-1)/2