Question

1.28.7g硫酸锌晶体 （ZnSO4、xH2O）加热使其失去全部结晶水冷却后称量,其质量为16.1g,试求该晶体中x的

Answer 1

1.ZnSO4 的物质的量不变：

28.7 :(161+18x) = 16.1 :161

x = (287-161)/18 = 7

2.NaCl x g,NaI y g:

2NaI + Cl2 = 2NaCl + I2

300.117

y.117y/300

x+117y/300 = 11.7

x+y = 20.85

x = 5.85g,y=15.0g

NaCl 5.85g,NaI 15.0g