sin105°=?sin75°=?sin15°=?

4个回答

  • sin105°

    = sin(45°+60°)

    = sin45°cos60°+cos45°sin60°

    = √2/2*½+√2/2*√3/2

    = √2/4+√6/4

    = (√2+√6)/4

    sin75°

    = sin(45°+30°)

    = sin45°cos30°+cos45°sin30°

    = √2/2*√3/2+√2/2*½

    = (√2+√6)/4

    sin15°

    = sin(45°-30°)

    = sin45°cos30°-cos45°sin30°

    = √2/2*√3/2-√2/2*½

    =(√6-√2)/4