Question

计算【(a-b)的4次方+3(b-a)的3次方+2(b-a)的平方】除以【2分之1(a-b)】的平方

Answer 1

[(a-b)^4 + 3(b-a)^3+2(b-a)^2] / [ (a-b)/2 ]

= 2[(a-b)^4 - 3(a-b)^3+2(a-b)^2] / [ (a-b) ]

=2[(a-b)^3 - 3(a-b)^2+2(a-b) ]

=2(a-b)[(a-b)^2 - 3(a-b)+2]

=2(a-b)(a-b-1)(a-b-2)