函数y=sin(wx+π/3)(w.0)在[π/4,π/2]上是减函数,求w
解析：∵函数y=sin(wx+π/3)(w>0)
∴函数y初相为第一象限角,离Y轴最近的极值点为最大值点
极大值点：wx+π/3=2kπ+π/2==>x=2kπ/w+π/(6w)
极小值点：wx+π/3=2kπ+3π/2==>x=2kπ/w+7π/(6w)
∵在[π/4,π/2]上是减函数
∴π/(6w)w>=2/3
7π/(6w)>=π/2==>w
函数y=sin(wx+π/3)(w.0)在[π/4,π/2]上是减函数,求w 求解
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