从中可以计算Al3+的浓度是0.3mol/L,取250ml混合溶液,Al3+为0.075mol ,Mg2+为0.05mol
Al3+ +4OH-=Alo2-+H2O
Mg2+ +2OH-=Mg(OH)2
所需OH-为0.075*4+0.05*2=0.4mol
体积=0.4|∕4=0.1L
从中可以计算Al3+的浓度是0.3mol/L,取250ml混合溶液,Al3+为0.075mol ,Mg2+为0.05mol
Al3+ +4OH-=Alo2-+H2O
Mg2+ +2OH-=Mg(OH)2
所需OH-为0.075*4+0.05*2=0.4mol
体积=0.4|∕4=0.1L