求50道计算题,50道一元一次方程(七年级的)

1个回答

  • 1、7(2x-1)-3(4x-1)=4(3x+2)-1;

    2、(5y+1)+ (1-y)= (9y+1)+ (1-3y);

    3、20%+(1-20%)(320-x)=320×40%

    4、2(x-2)+2=x+1

    5、2(x-2)-3(4x-1)=9(1-x)

    6、x/3 -5 = (5-x)/2

    7、2(x+1) /3=5(x+1) /6 -1

    8、(1/5)x +1 =(2x+1)/4

    9、(5-2)/2 - (4+x)/3 =1

    10、x/3 -1 = (1-x)/2

    11、(x-2)/2 - (3x-2)/4 =-1

    12、11x+64-2x=100-9x

    13、15-(8-5x)=7x+(4-3x)

    14、3(x-7)-2[9-4(2-x)]=22

    15、3/2[2/3(1/4x-1)-2]-x=2

    16、2(x-2)-3(4x-1)=9(1-x)

    17、11x+64-2x=100-9x

    18、15-(8-5x)=7x+(4-3x)

    19、3(x-7)-2[9-4(2-x)]=22

    20、3/2[2/3(1/4x-1)-2]-x=2

    21、2(x-2)+2=x+1

    1.7(2x-1)-3(4x-1)=4(3x+2)-1

    2.(5y+1)+ (1-y)= (9y+1)+ (1-3y)

    3.[ (- 2)-4 ]=x+2

    4.20%+(1-20%)(320-x)=320×40%

    5.2(x-2)+2=x+1

    6.2(x-2)-3(4x-1)=9(1-x)

    7.11x+64-2x=100-9x

    8.15-(8-5x)=7x+(4-3x)

    9.3(x-7)-2[9-4(2-x)]=22

    10.3/2[2/3(1/4x-1)-2]-x=2

    11.5x+1-2x=3x-2

    12.3y-4=2y+1

    13.87X*13=5

    14.7Z/93=41

    15.15X+863-65X=54

    16.58Y*55=27489

    17.2(x+2)+4=9

    18.2(x+4)=10

    19.3(x-5)=18

    20.4x+8=2(x-1)

    21.3(x+3)=9+x

    22.6(x/2+1)=12

    23.9(x+6)=63

    24.2+x=2(x-1/2)

    25.8x+3(1-x)=-2

    26.7+x-2(x-1)=1

    27.x/3 -5 = (5-x)/2

    28.2(x+1) /3=5(x+1) /6 -1

    29.(1/5)x +1 =(2x+1)/4

    30.(5-2)/2 - (4+x)/3 =1

    1.2(x-2)-3(4x-1)=9(1-x)

    2.11x+64-2x=100-9x

    3.15-(8-5x)=7x+(4-3x)

    4.3(x-7)-2[9-4(2-x)]=22

    5.3/2[2/3(1/4x-1)-2]-x=2

    6.2(x-2)+2=x+1

    7.0.4(x-0.2)+1.5=0.7x-0.38

    8.30x-10(10-x)=100

    9.4(x+2)=5(x-2)

    10.120-4(x+5)=25

    11.15x+863-65x=54

    12.12.3(x-2)+1=x-(2x-1)

    13.11x+64-2x=100-9x

    14.14.59+x-25.31=0

    15.x-48.32+78.51=80

    16.820-16x=45.5×8

    17.(x-6)×7=2x

    18.3x+x=18

    19.0.8+3.2=7.2

    20.12.5-3x=6.5

    21.1.2(x-0.64)=0.54

    22.x+12.5=3.5x

    23.8x-22.8=1.2

    24.1/50x+10=60

    25.2/ 60x-30=20

    26.3/ 3^20x+50=110

    27.4/ 2x=5x-3

    28.5/ 90=10+x

    29.6/ 90+20x=30