Question

一道化学计算题取100mL98%H2SO4(密度为1.84g/cm3）与铜共热,发生反应的化学方程式为：Cu+2H2SO

Answer 1

(1) n(H2SO4)=100*1.84*98%/98 = 1.84 mol

[H2SO4] = n(H2SO4)/V = 1.84/(100/1000) =18.4 mol/L

(2) Cu+2H2SO4(浓)===CuSO4+SO2+2H2O（条件加热）

n(SO2) = 8.96/22.4 = 0.4 mol

n(H2SO4) = 1.84 - 2*0.4 = 1.04 mol

[H2SO4] = 1.04/(400/1000) = 2.6 mol/L

(3) BaCl2 + H2SO4 = BaSO4 + 2HCl

n(BaSO4) = 2.6*(10/1000) = 0.026 mol