Question

2分之1+4分之1+8分之1+16分之1+32分之1+64分之1

Answer 1

解法一：原式=1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/64

=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64

=1/2+1/4+1/8+(1/16+1/16)-1/64

=.

=(1/2+1/2)-1/64

=1-1/64

=63/64

解法二：设原式=S,两边同时乘以64,则

64S=32+16+8+4+2+1=63

因此 S=63/64

解法三：原式=1/64(32+16+8+4+2+1)

=1/64*63

=63/64