Question

1、化简算式求值：（要有具体步骤）

Answer 1

(2+1)(2^2+1)(2^4+1)(2^8+901)(2^16+1)(2^32+1)

=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+901)(2^16+1)(2^32+1)

=(2^2-1)(2^2+1)(2^4+1)(2^8+901)(2^16+1)(2^32+1)

=(2^4-1)(2^4+1)(2^8+901)(2^16+1)(2^32+1)

=……………………………………

=2^64-1

n^2+(n(n+1))^2+(n+1)^2=(n(n+1)+1)^2

(道理嘛…………………………您把式子展开就知道了)