Question

用秦九韶算法计算多项式f(x)=2*x^7+x^6-3*x^3+2*x当x=2时的函数值

Answer 1

f(x)=x*(2*x^6+x^5-3*x^2+2)

=x*(x^2*(2*x^4+x^3-3)+2)

=x*(x^2*(x^3*(2*x+1)-3)+2)

代入x=2

f(x)=x*(x^2*(x^3*5-3)+2)

=x*(x^2*37+2)

=x*150

=300