计算:[(x-1)/(x²-x-2)]²÷(x²-2x+1)/(2-x)÷1/(x²+x0]²÷2x

2个回答

  • [(x-1)/(x²-x-2)]²÷(x²-2x+1)/(2-x)÷[1/(x²+x)]²÷2x

    =[(x-1)/(x-2)(x+1)]²÷(x-1)²/(2-x)÷[1/x(x+1)]²÷2x

    =(x-1)²/(x-2)²(x+1)²÷(x-1)²/(2-x)÷1/x²(x+1)²÷2x

    =[(x-1)²/(x-2)²(x+1)²*(2-x)/(x-1)²]÷1/x²(x+1)²÷2x

    =1/(2-x)(x+1)²÷1/x²(x+1)²÷2x

    =[1/(2-x)(x+1)²*x²(x+1)²]÷2x

    =x²/(2-x)÷2x

    =x/(4-2x)