Question

解下列方程16x-40=9x+164x=20/3x+162(3-x)=-4(x+5)3(-2x-5)+2x=91/2(x

Answer 1

(1)16x-40=9x+167x=56x=8(2) 4x=20/3x+16 8/3x=-16x=-6(3)2(3-x)=-4(x+5)6-2x=-4x-202x=-26x=-13(4)3(-2x-5)+2x=9-6x-15+2x=94x=-24x=-6(5)1/2(x-4)-(3x+4)=-15/2 x/2-2-3x-4=-15/2-5x/2-6=-15/2-5x-12=-15 -5x=-3 x...