Question

0.5mol/L的硫酸溶液ph是多少?

Answer 1

c(H+) = 2 c(H2SO4) = 2 * 0.5 = 1 mol/L

pH = - lg c(H+) = - lg 1 = 0

所以 0.5 mol/L的硫酸溶液pH为0