解方程组:{x²-2xy+3y²=9 4x²-5xy+6y²=30

1个回答

  • x2-2xy+3y2=9

    得:x2=9-(-2xy+3y2)带入4x2-5xy+6y2=30

    得:4*(9-(-2xy+3y2)-5xy+6y2=30

    得:2y2-xy-2=0带入x2-2xy+3y2=9

    得x2=y2+5

    由2y2-xy-2=0

    得2y2-xy-2=0

    即x=2(y-1/y)带入x2=y2+5

    得4*(y2-2+1/y2)=y2+5

    得3*y2-13+4/y2=0

    3*y2*y2-13*y2+4=0

    (3*y2-1)(y2-4)=0

    得y2=1/3 x2=16/5

    或y2=4 x2=9

    再解出x,y 即可.