Question

求极限limx^2/x-1 x->1

Answer 1

先取对数原式化为lim(x-->0)ln[(x+e^2x-1)+1]/x=lim(x-->0)[e^2x-1+x]/x

=lim(x-->0)e^2x-1/x+lim(x-->0)x/x=3

所以原极限就是e^3