Question

解方程组：{（x+2)^2-(y-3)^2=(x+y)(x-y) { x-3y=2

Answer 1

(x+2)^2-(y-3)^2=(x+y)(x-y) .(1)

x-3y=2 .(2)

由（1）得：

x²+4x+4-y²+6y-9=x²-y²

4x+6y=5 .(3)

(2)*2+(3)：

2x+4x = 4+5

6x=9

x=3/2

代入（2）得：

3/2-3y=2

3-6y=4

66=-1

y=-1/6