初一的三道二元一次方程!急用!① [ 2(x-y)]/3 - [x+y]/4=-16(x+y) - 4(2x-y)=16

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  • ① [ 2(x-y)]/3 - [x+y]/4=-1 (1)

    6(x+y) - 4(2x-y)=16 (2)

    由(1)得

    8(x-y)-3(x+y)=-12

    5x-11y=-12 (3)

    由(2)得

    6x+6y-8x+4y=16

    -2x+10y=16

    x-5y=-8 (4)

    解(3)(4)得

    x=2

    y=2

    ② [x+1]/5=[y-3]/2 (1)

    3x+4y=32 (2)

    由(1)得 2x+2=5y-15

    2x-5y=-17

    6x-15y=-51 (3)

    (2)*2-(3)得 23y=115

    y=5

    把y=5代入(2) 得

    x=4

    ∴x=4

    y=5

    ③ [3x+2y]/4=[2x+y]/5 (1)

    [3x+2y]/4=[x-y+1]/6 (2)

    由(1)得 15x+10y=8x+4y

    7x+6y=0 (3)

    由(2)得 9x+6y=2x-2y+2

    7x+8y=2 (4)

    解(3)(4)得

    x=-6/7

    y=1