Question

2(x-1)平方分之X三次方-2的导函数是什么

Answer 1

y=(x^3-2)/[2(x-1)^2],

y'=(1/2)[(x^3-2)'(x-1)^2-2(x-1)*(x^3-2)]/(x-1)^4

=(1/2)[3x^2*(x-1)^2-2(x-1)*(x^3-2)]/(x-1)^4

=(1/2)[(x-1)(3x^3-3x^2-2x^3+4)]/(x-1)^4

=(x-2)^2(x+1)/[2(x-1)^3].