Question

奇函数FX满足F(2)=1,F(X+2)=F(X)+F(2)则F(5)=

Answer 1

奇函数,F(0)=0,

F(X+2)=F(X)+F(2)

F(-1)=-F(1)

F(1)=F(-1+2)=F(-1)+F(2)＝-F(1)+1

F(1)=0.5

故有：F(3)=F(1+2)=F(1)+F(2)＝1.5

F(5)=F(2+3)=F(2)+F(3)=2.5