Question

就一道二次函数计算题.(1)y=3x^2-4x+1配方阿...要通俗易懂.过程最好不要跳.

Answer 1

y=3x^2-4x+1 =3[x^2-(4/3)x]+1=3(x-2/3)^2-3*(2/3)^2+1=

=3(x-2/3)^2-3*(4/9)+1=3(x-2/3)^2-(4/3)+1=3(x-2/3)^2-1/3