已知 f(x)= sin(x-3π)•cos(2π

1个回答

根据题意，得 f(x)= sin(x-3π)•cos(2π-x)•sin(-x+ 3π 2 ) cos(-x-π)•cos( π 2 -x) = -sinx•cosx•sin(-x- π 2 ) -cosx•sinx =sin（-x- π 2...

已知f(x)＝sin(x−3π)•cos(2π−x)•sin(−x+3π2)cos(−x−π)•cos(π2−x)
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)]
f(x)sinx·sin(π-x)+√3sin(π/2+x)cos(π/2+x)+2cos(π+x)cos(π-x) 求
已知f（x）=sin(5π2+x)cos(x−π2)•sin（x+π）•cos（π-x）．
若sin(x-π)=2cos(2π-x),求(sin(π-x)+5cos(2π-x))/(3cos(π-x)-sin(-
已知函数f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]
已知函数f(x)=2√3sin(x/2+π)cos(x/2+π/4)-sin(x+π)
已tanx=4/3,求cos(2x-π/3)cos(π/3-x)-sin(2x-π/3)sin(π/3-x)
已知f(x)=(sin(π-x)*cos(2π-x))/cos(-π-x)*tan(π-x),则f(-31π/3)的值为
已知函数 f(x)=cos(2x- π 3 )+2sin(x- π 4 )sin(x+ π 4 ) ．