Question

复合函数 求导数 F（x）=ln {(x+1)^4 * (7x-1)^3/(x^2+6)^1/2},先化简,再求导!.

Answer 1

F(x)=ln[(x+1)^4]+ln[(7x-1)^3]-ln[(x^2+6)^1/2]

=4*ln(x+1)+3*ln(7x-1)-[ln(x^2+6)]/2

F'=4/(x+1)+21/(7x-1)-x/(x^2+6);