Question

(-xy的-2次幂）的-2次幂乘以（-2x的-3次幂y的-1次幂）的-3次幂.

Answer 1

[-xy^(-2）]^(-2)*[-2x^(-3)y^(-1)]^(-3)

=x^(-2)y^4*(-1/8)x^6y^3

=(-1/8)x^(-2+6)y^(4+3)

=-x^4y^7/8