求解2个线性方程 1.k1-k2+3k3=0 3k1+k2+k3=0 -k1+2k2-5k3=0 2.k1-k2+2k3

1个回答

  • 1.解: 系数矩阵=

    1 -1 3

    3 1 1

    -1 2 -5

    r2-3r1, r3+r1

    1 -1 3

    0 4 -8

    0 1 -2

    r1+r3,r2-4r3

    1 0 1

    0 0 0

    0 1 -2

    方程组的解为: c(-1,2,1)^T.

    2.

    解: 增广矩阵 =

    1 -1 2 -1

    3 1 0 2

    1 3 -4 4

    r2-3r1,r3-r1

    1 -1 2 -1

    0 4 -6 5

    0 4 -6 5

    r3-r2,r2*(1/4),r1+r2

    1 0 1/2 1/4

    0 1 -3/2 5/4

    0 0 0 0

    方程组的解为: (1/4,5/4,0)^T+c(-1,3,2)^T.