Question

化简sin(x+2π/3)+2sinx-√3 cos(π/3-x) 主要看过程谢谢~

Answer 1

=sinxcos2π/3+cosxsin2π/3+2sinx-√3(cosxcosπ/3+sinxsinπ/3)

=sinx *(-1/2+2 -√3*√3/2)+cosx * (√3/2-√3/2)

=0;

或

=sin(π/3-x) +2sinx-√3 cos(π/3-x)

=2sin(π/3-x) cosπ/3-2cos(π/3-x)sinπ/3+2sinx

=2sin(π/3-x-π/3)+2sinx

=-2sinx++2sinx

=0