Question

求解高等数学的简单版不定积分解题思路

Answer 1

1, ∫lnxdx/x =∫lnxdlnx = (lnx)^2/2+C.

2. ∫dx/(sin2x)^2 = ∫(csc2x)^2]dx = (1/2)∫(csc2x)^2]d(2x)

= (-1/2)cot2x+C

3. ∫cosxdx/sinx =∫dsinx/sinx = ln|sinx|+C.

4. ∫dx/(cos2x)^2 = ∫(sec2x)^2]dx = (1/2)∫(sec2x)^2]d(2x)

= (1/2)tan2x+C