Question

在命令行中携带若干个数值,找出这些数中的最大值、最小值和平均值

Answer 1

我估计你问的应该是java的吧,下面是代码和截图,希望对你有用.

import java.util.Arrays;

public class NumberHandle {

public static void main(String []args){

//String arr[] = {"1","2","5","4","3"};

System.out.println("最大值："+getMax(args));

System.out.println("最小值："+getMin(args));

System.out.println("平均值："+getAverage(args));

}

//最大值

public static int getMax(String arr[]){

int ar[] = new int[arr.length];

for(int s = 0;s < arr.length;s ++){

ar[s] = Integer.parseInt(arr[s]);

}

int l = ar.length;

Arrays.sort(ar);

int max = ar[l -1];

return max;

}

//最小值

public static int getMin(String arr[]){

int ar[] = new int[arr.length];

for(int s = 0;s < arr.length;s ++){

ar[s] = Integer.parseInt(arr[s]);

}

int l = ar.length;

Arrays.sort(ar);

int min = ar[0];

return min;

}

//平均值

public static int getAverage(String[] arr){

int ar[] = new int[arr.length];

for(int s = 0;s < arr.length;s ++){

ar[s] = Integer.parseInt(arr[s]);

}

int l = ar.length;

int sum = 0;

for(int i = 0;i < l;i ++){

sum = sum+ar[i];

}

int average = sum / l;

return average;

}

}