求∫(0,1)e^2xdx的定积分和过程

2个回答

∫(0,1)e^2xdx
=(1/2)∫e^(2x)d(2x) [0,1]
=(1/2)e^(2x)+C [0,1]
=(1/2)(e²-1)
=e²/2-(1/2)