Question

2(根号下x+根号下y-1+根号下z-2)=x+y+z,求x,y,z的值

Answer 1

经配方得（根号下x -1）²+ （根号下y-1 -1）²+ （根号下z-2 -1）²=0

∴ x=y-1=z-2=0

∴x=0,y=1,z=2