|sin(x/2-π/6)+1/2|周期怎么求
1个回答
∵sin(x/2-π/6)+1/2的最小正周期T=2π/(1/2)=4π
∴|sin(x/2-π/6)+1/2|的最小正周期是2π
相关问题
求下列函数周期:y=sin1/2x和y=2sin(x/3-π/6)突然忘记周期怎么求了.≥﹏≤
sin(2x+π/6)的最小正周期怎么求
f(x)=sin(x+π/6)+sin(x-π/6)+2cos^2(x/2)+a,求最小正周期,[-π/2,π/2]上最
设F(X)=sin(πx/4-π/6)-2cos(πx/8)2+1求最小正周期
sin2πx+cos2πx的周期 sin2πxcos2πx的周期
y=sin(π+2x)cos(π-2x)求周期
求值sin²x+cos²(π/6+x)+1/2sin(2x+π/6)
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cos2x+a,(1)求函数的最小正周期及单调
y=|sin(2x+π/4)|的周期为π/2,而y=|sin(2x+π/4)+1/2|的周期为π
y=1+sinπx的周期~1+sinπ(X+2n)=1+sin(πX+2nπ)=1+sinπXcos2nπ+cosπXs