Question

分式方程,我不会做,大家帮个忙啊!

Answer 1

1/(x-10)+1/(x-6)=1/(x-7)=1/(x-9)

3/[(x-10)(x-7)]=3/[(x-6)(x-9)]

(x-10)(x-7)=(x-6)(x-9)

(x-10)/(x-6)=(x-9)/(x-7)

[(x-8)-2]/[(x-8)+2]=[(x-8)-1]/[(x-8)+1]

……