Question

计算方程组s=2(t-9)+3(t-5),s=(t+3)/2-(t+2)/3

Answer 1

s=2(t-9)+3(t-5) (1)

s=(t+3)/2-(t+2)/3 (2)

化简（1）得：

s=5t-33 带入（2）得：

5t-33=(t+3)/2-(t+2)/3

解t=7

则s=2