1/x-7-1/x-5=1/x-6-1/x-4
1/x-7+1/x-4=1/x-6+1/x-5
(x-4+x-7)/(x-7)(x-4)=(x-5+x-6)/(x-6)(x-5)
(2x-11)/(x^2-4x-7x+28)=(2x-11)/(x^2-5x-6x+30)
(2x-11)(x^2-4x-7x+28)=(2x-11)(x^2-5x-6x+30)
(2x-11)(x^2-11x+28-x^2+11x-30)=0
(2x-11)=0
x=11/2
解方程:1/x-7-1/x-5=1/x-6-1/x-4
3个回答
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