x²-6x-10-9=0
x²-6x-19=0
a=1,b=-6,c=-19
b²-4ac=(-6)²-4×1×(-19)=112>0
则原方程有两不相等实数根
x1=(6-√112)/2=3-4√7
x2=(6+√112)/2=3+4√7