Question

求:0.1mol/lNH3溶液的PH及PH.及解离度（PKNH3=4.75）.若向一升该溶液中加入0

Answer 1

NH3 + H2O NH4+ + OH-

pKb=4.75

Kb=10^-4.75=[OH-]^2/0.1

[OH-]=0.00133 mol/L

pOH=2.88,pH=14-pOH=11.12

解离度＝1.33x10^-3／0.1=1.33x10^-2=1.33%

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pH=pKa=14-pKb=9.24