Question

利用等价无穷小的性质,求下列极限

Answer 1

首先化简：lim [（tanX-sinX)/(sinX)^3] =lim [（sinX/cosX-sinX)/(sinX)^3] =lim [（1/cosX-1)/(sinX)^2] =lim [(1-cosx)/cosx]/(sinX)^2因为1-cosx与1/2(sinX)^2代入得lim [1/2(sinX)^2/cosx]/(sinX)^2=1/2(答案有...